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Previous Year Question (PYQs)



Consider a machine with $16\ GB$ main memory and $32$-bits virtual address space, with page size as $4KB$. Frame size and page size is same for the given machine.

Find number of pages required for the given virtual address space.





Solution

Virtual address space $=32$ bits

So, total virtual memory size:

$2^{32}$ bytes

Page size $=4KB=2^{12}$ bytes

Number of pages:

$\frac{2^{32}}{2^{12}}=2^{20}$


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