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A digital computer has a common bus system for $8$ registers $16$ bits each. How many multiplexers are required to implement common bus? What size of multiplexers is required?





Solution

There are $8$ registers and each register has $16$ bits.

Common bus size must be $16$ bits.

For each bit position, one multiplexer is required.

So, number of multiplexers required is $16$.

Each multiplexer must select one bit from $8$ registers.

So, each multiplexer is of size $8\times1$.


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