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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
A company has a choice of two languages $L_1$ and $L_2$ to develop a software for their client. Number of LOC required to develop an application in $L_2$ is thrice the LOC in language $L_1$. Also, software has to be maintained for next $10$ years. Various parameters for two languages are given below to decide which language should be preferred for development.
Total cost of project includes cost of development and maintenance. What is the LOC for $L_1$ for which cost of developing the software with both languages must be same?
| PARAMETER | $L_1$ | $L_2$ |
|---|---|---|
| Man-year needed for development | LOC/1000 | LOC/1000 |
| Development cost | Rs. 70,000 | Rs. 90,000 |
| Cost of Maintenance per year | Rs. 1,00,000 | Rs. 40,000 |
Solution
Let LOC for $L_1=x$Then LOC for $L_2=3x$
For $L_1$:
Development cost $=\frac{x}{1000}\times70000=70x$
Maintenance cost for $10$ years:
$10\times100000=1000000$
Total cost for $L_1$:
$70x+1000000$
For $L_2$:
Development cost $=\frac{3x}{1000}\times90000=270x$
Maintenance cost for $10$ years:
$10\times40000=400000$
Total cost for $L_2$:
$270x+400000$
Now both costs are same:
$70x+1000000=270x+400000$
$600000=200x$
$x=3000$
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