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Given below are two statements:

Statement I: The laws of nature put two fundamental limits on the data rate of a channel. The H. Nyquist limit restricts the number of independent samples per second to twice the bandwidth in a noiseless channel.

Statement II: Shannon's major result about noisy channel is that the maximum data rate of a channel whose bandwidth is $H$ Hz, and whose signal-to-noise ratio is $\frac{S}{N}$ is given by:

Maximum number of bits/sec $=H\log_2\left(1+\frac{S}{N}\right)$

In the light of the above statements, choose the correct answer from the options given below:





Solution

Statement I is true.

Nyquist theorem gives the limit for a noiseless channel.

It says that for a channel of bandwidth $H$, the maximum number of independent samples per second is $2H$.

So, Statement I is true.

Statement II is also true.

Shannon capacity theorem gives the maximum data rate of a noisy channel as:

$C=H\log_2\left(1+\frac{S}{N}\right)$

where $H$ is bandwidth and $\frac{S}{N}$ is signal-to-noise ratio.

Therefore, both statements are true.


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