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Previous Year Question (PYQs)
2
concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.
What is the capacity of the disk, in bytes?
Solution
Given,
Sector size $=512$ bytes
Sectors per track $=50$
Tracks per surface $=2000$
Number of double-sided platters $=5$
So, number of surfaces:
$5\times 2=10$
Capacity of one track:
$512\times 50=25600$ bytes
Since,
$1K=1024$ bytes
So,
$\frac{25600}{1024}=25K$
Capacity of one surface:
$25K\times 2000=50000K$
Capacity of total disk:
$50000K\times 10=500000K$
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