Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET

Previous Year Question (PYQs)



concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.

What is the capacity of the disk, in bytes?





Solution

Given,

Sector size $=512$ bytes

Sectors per track $=50$

Tracks per surface $=2000$

Number of double-sided platters $=5$

So, number of surfaces:

$5\times 2=10$

Capacity of one track:

$512\times 50=25600$ bytes

Since,

$1K=1024$ bytes

So,

$\frac{25600}{1024}=25K$

Capacity of one surface:

$25K\times 2000=50000K$

Capacity of total disk:

$50000K\times 10=500000K$


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

loading...