Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET

Previous Year Question (PYQs)



concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.

If the disk platters rotate at $5400$ rpm, then approximately what is the maximum rotational delay?





Solution

Given,

Rotational speed $=5400$ rpm

It means:

$5400$ revolutions in $60$ seconds

So, revolutions per second:

$\frac{5400}{60}=90$

Time taken for one revolution:

$\frac{1}{90}$ seconds

$=0.0111$ seconds

Maximum rotational delay is equal to time for one full revolution.

So, maximum rotational delay is approximately:

$0.011$ seconds


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

loading...