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concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.

If one track of data can be transferred per revolution, then what is the data transfer rate?





Solution

From previous calculation, capacity of one track is:

$25K$ bytes

Given rotational speed:

$5400$ rpm

Revolutions per second:

$\frac{5400}{60}=90$

If one track of data is transferred per revolution, then data transferred per second is:

$25K\times 90$

$=2250K$ bytes/second

So, data transfer rate is:

$2250$ KBytes/second


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