Given,
$P(X\text{ passes})=\frac{2}{5}$
So,
$P(X\text{ does not pass})=1-\frac{2}{5}=\frac{3}{5}$
Also,
$P(Y\text{ passes})=\frac{3}{4}$
So,
$P(Y\text{ does not pass})=1-\frac{3}{4}=\frac{1}{4}$
Since both events are independent,
$P(\text{neither }X\text{ nor }Y\text{ passes})=\frac{3}{5}\times \frac{1}{4}$
$=\frac{3}{20}$
Online Test Series, Information About Examination,
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Online Test Series, Information About Examination,
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and More.