Total instruction size is:
$16$ bits
Opcode uses:
$4$ bits
So, remaining bits for memory address are:
$16-4=12$ bits
With $12$ address bits, maximum addressable memory locations are:
$2^{12}=4096$
Online Test Series, Information About Examination,
Syllabus, Notification
and More.
Online Test Series, Information About Examination,
Syllabus, Notification
and More.