How many ways are there to place $8$ indistinguishable balls into four distinguishable bins?
Let the number of balls in four distinguishable bins be $x_1,x_2,x_3,x_4$.
Then,
$x_1+x_2+x_3+x_4=8$
Here, balls are indistinguishable and bins are distinguishable.
So, the number of non-negative integral solutions is
${}^{n+r-1}C_{r-1}$
Here, $n=8$ and $r=4$.
So,
${}^{8+4-1}C_{4-1}={}^{11}C_{3}$
$=\dfrac{11 \times 10 \times 9}{3 \times 2 \times 1}$
$=165$
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