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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
A computer uses a memory unit with $256K$ words of $32$ bits each. A binary instruction code is stored in one word of memory. The instruction has four parts: an indirect bit, an operation code and a register code part to specify one of $64$ registers and an address part. How many bits are there in the operation code, the register code part and the address part?
Solution
Memory size is
$256K=256\times 1024=2^8\times 2^{10}=2^{18}$ words
So, address part requires
$18$ bits
Number of registers is
$64=2^6$
So, register code requires
$6$ bits
Instruction size is
$32$ bits
Indirect bit requires
$1$ bit
So, operation code bits are
$32-1-6-18=7$
Therefore, operation code, register code and address part are
$7,6,18$
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