Solution

Insert elements one by one into max-heap.

After inserting $42,25,30$:

$\langle 42,25,30\rangle$

Insert $40$.

Since $40>25$, swap them:

$\langle 42,40,30,25\rangle$

Insert $22$:

$\langle 42,40,30,25,22\rangle$

Insert $35$.

Since $35>30$, swap them:

$\langle 42,40,35,25,22,30\rangle$

Insert $26$.

No swap is needed.

Final max-heap array is

$\langle 42,40,35,25,22,30,26\rangle$