Question: Find the base r such that
(312)r ÷ (20)r = (13.1)r
(3r² + r + 2) / (2r) = r + 3 + 1/r
3r² + r + 2 = 2r² + 6r + 2
r² - 5r = 0
⇒ r(r - 5) = 0
Since base must be > 1, the valid solution is:
Base (radix) = 5
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Commented Oct 17 , 2023
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